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- 11/18/14 15:15:17 (10 years ago)
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v2 v3 30 30 '''2.5 D''' 31 31 32 This is cylindrical geometry with axial symmetry. Therefore we begin with the Laplacian in cylindrical , throwing out the theta derivetive:32 This is cylindrical geometry with axial symmetry. Therefore we begin with the Laplacian in cylindrical coordinates, throwing out the theta derivative: 33 33 34 [[latex($ \triangledown ^2_{(2.5D)} = \frac{1}{r}\frac{\partial }{\partial r}(r\frac{\partial}{\partial r}) + \frac {\partial ^2}{\partial z ^2} = \frac{1}{r} [\frac{\partial}{\partial r} + r \frac{\partial^2}{\partial r ^2}] + \frac{\partial ^2}{\partial z^2}$)]] 35 36 Expanding out and putting into Poisson equation, 37 38 [[latex($ \frac{1}{r}\frac{D }{Dr} \phi_{r,z} + \frac{D^2}{D r^2}\phi_{r,z} + \frac{D^2}{Dz^2} \phi_{r,z} = \rho_{r,z}$)]] 39 40 41