Changes between Version 11 and Version 12 of u/erica/scratch3
- Timestamp:
- 04/03/16 16:10:51 (9 years ago)
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u/erica/scratch3
v11 v12 87 87 From this equation, it is clear that h is the scale-height. Thus, by writing R as: 88 88 89 [[latex($R \approx |-\frac{ \tau_R}{h \rho}| \approx \frac{\tau_R}{h\rho}$)]]89 [[latex($R \approx |-\frac{1}{h \kappa_R\rho}| \approx \frac{1}{h \kappa_R\rho}$)]] 90 90 91 91 we can set h to be the distance between the sink and box side (h=L), and imagine it as the scale height for the radiation. … … 95 95 [[latex($\kappa_R=0.23~\frac{cm^2}{g}$)]] 96 96 97 for 10 K gas. 97 for 10 K gas. Recall that opacity ([[latex($\kappa$)]]) is related to the absorption coefficient ([[latex($\alpha$)]]) by, 98 99 [[latex($\kappa \rho=\alpha (cm^{-1})$)]] 100 101 (where the absorption coefficient reduces the intensity of the ray by [[latex($dI_\nu=-\alpha_\nu I_\nu ds$)]]) 98 102 99 103 This implies that the optical depth is, … … 101 105 [[latex($\tau_R\approx4.3~\frac{g}{cm^2}$)]] 102 106 107 108 Recall that optical depth, opacity, and mean free path are related by, 109 110 [[latex($$)]]