Changes between Version 3 and Version 4 of u/erica/radpredictionsink


Ignore:
Timestamp:
04/05/16 14:42:27 (9 years ago)
Author:
Erica Kaminski
Comment:

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  • u/erica/radpredictionsink

    v3 v4  
    2525[[Image(ic.png, 35%)]]
    2626
    27 Prediction: By 24 days, expect the diffusion wave to hit the boundary. Depending on the energy injection rate compared to the diffusion rate, the shape of the curve might be different. For instance, if energy injection rate (Er) >> diffusion rate (Dr), might expect the gaussian to be increasing in height as well as width. If Er = Dr, might expect the profile to be flat, as it grows in width. If Er << Dr, expect a gaussian that grows in width over time, but not height.
     27'''Prediction''': By 24 days, expect the diffusion wave to hit the boundary. Depending on the energy injection rate compared to the diffusion rate, the shape of the curve might be different. For instance, if energy injection rate (Er) >> diffusion rate (Dr), might expect the gaussian to be increasing in height as well as width. If Er = Dr, might expect the profile to be flat, as it grows in width. If Er << Dr, expect a gaussian that grows in width over time, but not height.
    2828
    29 Check: Make time curves of Erad(x), and check that the wave hits the boundary by t=24 days.
     29'''
     30Check''': Make time curves of Erad(x), and check that the wave hits the boundary by t=24 days.
    3031
    3132
    32 Prediction: The total thermal energy (and thus the total energy) should increase like t^2^. This is because,
     33'''Prediction''': The total thermal energy (and thus the total energy) should increase like t^2^. This is because,
    3334
    3435[[latex($\frac{\partial e}{\partial t} = -\kappa_P \rho (4 \pi B - cE)$)]], where
     
    4243This holds as long as 4 pi B << the energy injected each time step. That way we can effectively ignore changes to thermal energy induced by increasing B(T).
    4344
    44 Check: Make curve of e_total(t), E_total(t).
     45'''
     46Check''': Make curve of e_total(t), E_total(t).
    4547
    46 Prediction: The total radiative energy should increase as:
     48'''Prediction''': The total radiative energy should increase as:
    4749
    4850[[latex($\frac{dE_{rad}}{dt} = L$)]]
     
    5052[[latex($E_{rad}= Lt$)]]
    5153
    52 Check: Make curve of Erad_total(t).
     54'''Check''': Make curve of Erad_total(t).
     55
     56'''Prediction''': The thermal energy, e, of a zone immediately adjacent to the kernel should increase linearly. This is because, the difference between the energy injected into the grid, E*, and 4piB, is some height X (where X = L*dt-B). So, right next to kernel, expect the coupling time to go like:
     57
     58[[latex($\int de=\kappa_P \rho X \int dt$)]]
     59
     60Or,
     61
     62[[latex($\triangle e=\kappa_P \rho (L*dt-B) \triangle t$)]]
     63
     64*This assumes the energy injection rate is << diffusion rate, so that we know the difference in height between Erad and B*.
     65
     66'''Check''': Make a time query of a cell near the kernel.
     67
     68