Changes between Version 5 and Version 6 of u/erica/CF_spectra


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Timestamp:
01/05/15 13:17:16 (10 years ago)
Author:
Erica Kaminski
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  • u/erica/CF_spectra

    v5 v6  
    3131== Kinetic Energy ==
    3232
    33 There seems then to be 2 different ways of computing the power spectrum of the kinetic energy. First, we can take the fourier transform of [[latex($ \sqrt{\rho (v_x + v_y + v_z)^2}$)]] and then square this to get the power spectrum. Or, we can take [[latex($\sqrt{\rho v_x^2}$)]] and then sum up the squares of the various fourier transforms for each dimension.
     33There seems then to be 2 different ways of computing the power spectrum of the kinetic energy. First, we can take the fourier transform of [[latex($ \sqrt{\rho (v_x + v_y + v_z)^2}$)]] and then square this to get the power spectrum. Or, we can take [[latex($\sqrt{\rho v_x^2}$)]] and then sum up the squares of the various fourier transforms for each dimension. That is, does
     34
     35[[latex($(F(\sqrt{v_x^2 + v_y^2 + v_z^2} ~))^2 = (F(v_x))^2 + (F(v_y))^2 + (F(v_z))^2 ~?$)]]
     36
     37Further, which do we want,
     38
     39
     40[[latex($(F(\sqrt{\rho(v^2)} ~))^2 ~or~ (F(\sqrt{\rho}))^2*(F(v))^2 $)]]
     41
     42as it seems both give the same units..