Changes between Version 20 and Version 21 of SpectraObject

Timestamp:

01/13/15 15:08:50 (10 years ago)

Author:

Jonathan

Comment:

—

SpectraObject

@@ -134 +134 @@
 And again, the grid will be wrapped around in both x and y.  So a 10x10 transform will have components that correspond to the following points in k space. 
 
-[[Image(Screen Shot 2015-01-13 at 2.44.52 PM.png, width=400)]]
+[[Image(Screen Shot 2015-01-13 at 2.58.13 PM.png, width=400)]]
 
-Now since the normalization of the wavenumber goes like [[latex($\frac{2\pi}{L}$)]], if the region is not a square/cube, the spacing of the points in fourier space will not be uniform.  
+Now since the normalization of the wavenumber goes like [[latex($\frac{2\pi}{L}$)]], if the region is not a square/cube, the spacing of the points in k space will not be uniform.  
 
 For example, if [[latex($L_y = L_x/2$)]] then [[latex($\Delta k_y = 2 \Delta k_x$)]]
 
-So if our box is 10x5, and we use [[latex($\Delta k_x$)]] as our grid spacing
+So if our domain is 10x5, and we use [[latex($\Delta k_x$)]] to normalize our wave vectors, then we would have the following components.
 
-
-[[Image(Screen Shot 2015-01-13 at 2.53.55 PM.png, width=400)]]
+[[Image(Screen Shot 2015-01-13 at 2.57.25 PM.png, width=400)]]