Changes between Version 18 and Version 19 of SpectraObject

Timestamp:

01/13/15 14:55:37 (10 years ago)

Author:

Jonathan

Comment:

—

SpectraObject

@@ -132 +132 @@
 [[latex($F(\mathbf{k})=  \displaystyle \int_{y=0}^{L_y} \displaystyle \int_{x=0}^{L_x} e^{i\mathbf{k}\cdot \mathbf{x}} f(\mathbf{x}) dx dy =  \displaystyle \int_{y=0}^{L_y} e^{ik_y y} \left [ \displaystyle \int_{x=0}^{L_x} e^{ik_xx} \left [ f(\mathbf{x}) \right ]  dx \right ] dy  $)]]
 
-And again, the grid will be wrapped around in both x and y.  This means it will look like 
+And again, the grid will be wrapped around in both x and y.  So a 10x10 transform will have components that correspond to the following points in k space. 
 
-Now since the normalization of the wavenumber goes like [[latex($\frac{2\pi}{L}$)]], if the region is not a square/cube, the spacing of the points in fourier space will not be uniform.  For example, if [[latex($L_y = L_x/2$)]] then [[latex($\Delta y = 2 \Delta x$)]]
+[[Image(Screen Shot 2015-01-13 at 2.44.52 PM.png, width=400)]]
+
+Now since the normalization of the wavenumber goes like [[latex($\frac{2\pi}{L}$)]], if the region is not a square/cube, the spacing of the points in fourier space will not be uniform.  
+
+For example, if [[latex($L_y = L_x/2$)]] then [[latex($\Delta y = 2 \Delta x$)]]
+
+So if our box is 10x5, then 
+