Changes between Version 17 and Version 18 of SpectraObject


Ignore:
Timestamp:
01/13/15 14:48:54 (10 years ago)
Author:
Jonathan
Comment:

Legend:

Unmodified
Added
Removed
Modified
  • SpectraObject

    v17 v18  
    125125Or if we index the FFT array starting at 1, and then plot the index of each component on the corresponding grid in k space we get
    126126
     127[[Image(Screen Shot 2015-01-13 at 12.05.47 PM.png, width=400)]]
     128
     129=== MultiDimensional FFTs ===
     130A multidimensional DFT can be thought of as a sequence of 1D transforms in the way that a multidimensional Fourier transform is a sequence of 1D integrals.  That is
     131
     132[[latex($F(\mathbf{k})=  \displaystyle \int_{y=0}^{L_y} \displaystyle \int_{x=0}^{L_x} e^{i\mathbf{k}\cdot \mathbf{x}} f(\mathbf{x}) dx dy =  \displaystyle \int_{y=0}^{L_y} e^{ik_y y} \left [ \displaystyle \int_{x=0}^{L_x} e^{ik_xx} \left [ f(\mathbf{x}) \right ]  dx \right ] dy  $)]]
     133
     134And again, the grid will be wrapped around in both x and y.  This means it will look like
     135
     136Now since the normalization of the wavenumber goes like [[latex($\frac{2\pi}{L}$)]], if the region is not a square/cube, the spacing of the points in fourier space will not be uniform.  For example, if [[latex($L_y = L_x/2$)]] then [[latex($\Delta y = 2 \Delta x$)]]